Columbs law in vector form
Let the position vector of charges q1 and q2 be →r1 and →r2
We denote the force on q1 due to q2 by →F12 and the force on q2 due to q1 by →F21
F12=F21
Here →r1+→r12 =→r2
→r12=→r2−→r1
Also →r2+→r21=→r1
or →r21=→r1−→r2 and →r12=−→r21
The magnitude of vectors →r12 and →r21 is denoted by |→r12| and |→r21| and their unit vectors are given as
ˆr12=→r12 |→r12| and ˆr21=→r21 |→r21|
So the force →F12 and →F21 can be given as
→F12=14πϵo⋅q1q2|→r21|2ˆr21 & →F21=14πϵo⋅q1q2|→r12|2ˆr12
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