What is the absolute permittivity of a medium whose dielectric constant is one?
Ans. $\epsilon=\epsilon_0 \epsilon _r= \epsilon_0 \times 1= 8.85\times 10^{-12}C^2N^{-1}m^{-2}$
We provide materials and solutions to your school and college problems
What is the absolute permittivity of a medium whose dielectric constant is one?
Ans. $\epsilon=\epsilon_0 \epsilon _r= \epsilon_0 \times 1= 8.85\times 10^{-12}C^2N^{-1}m^{-2}$
No comments:
Post a Comment